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Question: Answered & Verified by Expert
A bar magnet of magnetic moment $\mathrm{M}$, is placed in a magnetic field of induction B. The torque exerted on it is
PhysicsMagnetic Properties of MatterVITEEEVITEEE 2017
Options:
  • A $\overrightarrow{\mathrm{M}} \cdot \overrightarrow{\mathrm{B}}$
  • B $-\overrightarrow{\mathrm{M}} \cdot \overrightarrow{\mathrm{B}}$
  • C $\overrightarrow{\mathrm{M}} \times \overrightarrow{\mathrm{B}}$
  • D $-\vec{B} \cdot \vec{M}$
Solution:
2124 Upvotes Verified Answer
The correct answer is: $\overrightarrow{\mathrm{M}} \times \overrightarrow{\mathrm{B}}$
$\tau=\mathrm{MB} \sin \theta=\overrightarrow{\mathrm{M}} \times \overrightarrow{\mathrm{B}}$

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