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A battery of emf $12 \mathrm{~V}$ and internal resistance $4 \Omega$ is connected to a resistor. The resistance of the resistor if the current in the circuit is $0.8 \mathrm{~A}$ is
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Verified Answer
The correct answer is:
$11 \Omega$
The circuit can be drawn as
Current in circuit,
$I=\frac{E}{r+R}$
Substituting given values, we get,
$0.8=\frac{12}{R+4}$
$\Rightarrow \quad R+4=15 \Rightarrow R=11 \Omega$
Current in circuit,
$I=\frac{E}{r+R}$
Substituting given values, we get,
$0.8=\frac{12}{R+4}$
$\Rightarrow \quad R+4=15 \Rightarrow R=11 \Omega$
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