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A battery of emf $\mathrm{E}$ and internal resistance $\mathrm{r}$ is connected with an external resistance $\mathrm{R}$ as shown in the figure. The battery will act as a constant voltage source if
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The correct answer is:
$r< < R$
$V_R=\frac{E}{(R+r)} \times R, \quad V_R=\frac{E}{(1+r / R)}$
$r < R, V_R \approx E$
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