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$A B C$ is a triangle in which $B C=10 \mathrm{~cm}, C A=6 \mathrm{~cm}$ and $A B=8 \mathrm{~cm} .$ Which one of the following is correct?
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Verified Answer
The correct answer is:
$A B C$ is a right angled triangle
Given a $\triangle \mathrm{ABC}$ in which $\mathrm{BC}=10 \mathrm{~cm}$, $\mathrm{CA}=6 \mathrm{~cm}$ and $\mathrm{AB}=8 \mathrm{~cm} .$
Since, $\mathrm{CA}^{2}+\mathrm{AB}^{2}=36+64=100=\mathrm{BC}^{2}$
$\therefore \Delta \mathrm{ABC}$ is a right angled triangle.
Since, $\mathrm{CA}^{2}+\mathrm{AB}^{2}=36+64=100=\mathrm{BC}^{2}$
$\therefore \Delta \mathrm{ABC}$ is a right angled triangle.
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