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$A B C$ is a triangle right-angled at $B$. The hypotenuse $(A C)$ is four times the perpendicular $(B D)$ drawn to it from the opposite vertex and $\mathrm{AD} < \mathrm{DC}$.
What is $\angle A B D_{?}$
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What is $\angle A B D_{?}$
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The correct answer is:
$15^{\circ}$
$\angle \mathrm{ABD}=\alpha=15^{\circ}$
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