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$A B C$ is right angled triangular plane of uniform thickness. The sides are such that $A B \gt B C$ as shown in figure. $I_1, I_2, I_3$ are moments of inertia about $A B, B C$ and $A C$, respectively. Then which of the following relations is correct?
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The correct answer is:
$I_2 \gt I_1 \gt I_3$
The moment of inertia of a body about an axis depends not only on the mass of the body but also on the distribution of mass about the axis. For a given body mass is same, so it will depend only on the distribution of mass about the axis. The mass is farthest from axis $B C$, so $I_2$ is maximum mass is nearest to axis $A C$, so $I_3$ is minimum.
Hence, the correct sequence will be $I_2 \gt I_1 \gt I_3$
Hence, the correct sequence will be $I_2 \gt I_1 \gt I_3$
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