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Question: Answered & Verified by Expert
A bead of mass m can slide without friction on a fixed circular horizontal ring of radius 3R having a centre at the point C. The bead is attached to one of the ends of spring with spring constant k. The natural length of spring is R and the other end of the spring is fixed at point O as shown in the figure. If the bead is released from position A, then the kinetic energy of the bead when it reaches point B is

PhysicsWork Power EnergyNEET
Options:
  • A 252kR2
  • B 92kR2
  • C 8kR2
  • D 12kR2
Solution:
2402 Upvotes Verified Answer
The correct answer is: 8kR2


Given,

Mass of bead =m

The radius of circular horizontal ring =3R

The natural length of spring =R

According to the conservation of energy,

KEi+PEi=KEf+PEf

   0+12kOA-R2=KEf+12kOB-R2

   0+12k5R-R2=KEf+12kR-R2

   KEf=8kR2

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