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A beam of fast moving alpha particles were directed towards a thin film of gold. The parts $A, B$ and $C$ of the transmitted and reflected beams corresponding to the incident parts $A, B$ and $C$ of the beam are shown in the adjoining diagram. The number of alpha particles in


PhysicsAtomic PhysicsKCETKCET 2020
Options:
  • A $B^{\prime}$ will be minimum and in $C^{\prime}$ maximum
  • B $A^{\prime}$ will be maximum and in $B^{\prime}$ minimum
  • C $A^{\prime}$ will be minimum and in $B^{\prime}$ maximum
  • D $C^{\prime}$ will be minimum and in $B^{\prime}$ maximum
Solution:
1320 Upvotes Verified Answer
The correct answer is: $A^{\prime}$ will be maximum and in $B^{\prime}$ minimum
According to Rutherford's $\alpha$-particles scattering experiment, following observations are made
(i) Most of the $\alpha$-particles passed through the gold foil undeflected.
(ii) Only about $0.14 \%$ of the incident $\alpha$-particles scattered by an angle greater than $1^{\circ}$.
(iii) About one $\alpha$-particle in every $8000 \alpha$-particles deflects by angle more than $90^{\circ}$.
So, from above observation, we can conclude about the number of $\alpha$-particle in given figure as,
$n_{A^{\prime}}>n_{C^{\prime}}>n_{B^{\prime}}$
i.e., number of $\alpha$-particle will be maximum in $A^{\prime}$ and minimum in $B^{\prime}$.

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