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Question: Answered & Verified by Expert
A beam of protons moving with a velocity $1.6 \times 10^5 \mathrm{~ms}^{-1}$ enter a uniform magnetic field of $\frac{\pi}{10} \mathrm{~T}$ at an angle $60^{\circ}$ to the direction of the field. The pitch of the helical path of the protons is (mass of proton $=1.6 \times 10^{-27} \mathrm{~kg}$)
PhysicsMagnetic Effects of CurrentAP EAMCETAP EAMCET 2017 (25 Apr Shift 2)
Options:
  • A $1.6 \times 10^{-2} \mathrm{~m}$
  • B $2.6 \times 10^{-2} \mathrm{~m}$
  • C $0.16 \times 10^{-2} \mathrm{~m}$
  • D $0.016 \times 10^{-2} \mathrm{~m}$
Solution:
1213 Upvotes Verified Answer
The correct answer is: $1.6 \times 10^{-2} \mathrm{~m}$
No solution. Refer to answer key.

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