A black body is at a temperature of 2880 K. The energy of radiation emitted by this object with wavelength between 499 nm and 500 nm is U 1 , between 999 nm and 1000 nm is U 2 and between 1499 nm and 1500 nm is U 3 . Wien's constant b = 2.88 x 10 6 nm - K, then

Question

A black body is at a temperature of 2880 K. The energy of radiation emitted by this object with wavelength between 499 nm and 500 nm is U 1 , between 999 nm and 1000 nm is U 2 and between 1499 nm and 1500 nm is U 3 . Wien's constant b = 2.88 x 10 6 nm - K, then, U 1 = 0, U 2 = 0, U 1 = U 2, U 2 > U 1

MARKS App · Accepted Answer

From Wien's law, λ m T = constant, where T is the temperature of black body and λ m is the wavelength corresponding to maximum energy of emission. Energy distribution of black body radiation is given below : i. U 1 and U 2 are not zero because a black body emits radiations of nearly all wavelengths. ii. Since U 1 corresponding to lower wavelength, U 3 corresponds to higher wavelength and U 2 corresponds to medium wave length hence U 2 > U 1 .

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