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A block is lying at rest inside a bus. The maximum acceleration of the bus such that the block remain stationary (the static friction coefficient $=02$, acceleration due to gravity $=10 \mathrm{~ms}^{-2}$ )
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The correct answer is:
$2 \mathrm{~ms}^{-2}$
Due to acceleration of bus, block experiences a backward acceleration $a$
Block will move if $m a \geq f$
Where, $f=$ friction force
$\begin{aligned} & \Rightarrow \quad m a \geq \mu m g \Rightarrow a \geq \mu g=0.2 \times 10 \\ & \Rightarrow \quad a \geq 2 \mathrm{~ms}^{-2}\end{aligned}$
Hence, maximum acceleration of the bus such that the block remain stationary is $2 \mathrm{~m} / \mathrm{s}^2$.
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