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A block mass $m$ is placed on a smooth wedge of inclination $\theta$. The whole system is accelerated horizontally so that the block does not slip on the wedge. The force exerted by the wedge on the block ( $g$ is acceleration due to gravity) will be:
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The correct answer is:
$\mathrm{mg} / \cos \theta$
Here $N \cos \theta=m g$
$\Rightarrow N=\frac{m g}{\cos \theta}$
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