The temperature of ice will increases from $-10℃ \mathrm{to}\mathrm{ }0\mathrm{℃}$ .
Heat supplied in this process will be
$Q=m{s}_i\left(10\right)$
Here, $m$=mass of ice
$s_i$=specific heat of ice
Then ice starts melting. Temperature during melting will remain constant ($0\mathrm{℃})$. Heat supplied in this process will be
$Q_2=mL \mathrm{w}\mathrm{h}\mathrm{e}\mathrm{r}\mathrm{e}, L=\mathrm{l}\mathrm{a}\mathrm{t}\mathrm{e}\mathrm{n}\mathrm{t}\mathrm{ }\mathrm{h}\mathrm{e}\mathrm{a}\mathrm{t}\mathrm{ }\mathrm{o}\mathrm{f}\mathrm{ }\mathrm{m}\mathrm{e}\mathrm{l}\mathrm{t}\mathrm{i}\mathrm{n}\mathrm{g}$
Now, the temperature of water will increase from $0℃ \mathrm{to}\mathrm{ }100\mathrm{℃}$ . Heat supplied will be ${\mathcal{Q}}_3=m{s}_w\left(100\right)$
where $s_w=\mathrm{s}\mathrm{p}\mathrm{e}\mathrm{c}\mathrm{i}\mathrm{f}\mathrm{i}\mathrm{c}\mathrm{ }\mathrm{h}\mathrm{e}\mathrm{a}\mathrm{t}\mathrm{ }\mathrm{o}\mathrm{f}\mathrm{ }\mathrm{w}\mathrm{a}\mathrm{t}\mathrm{e}\mathrm{r}$.
Finally water at 100$℃$ will be converted into steam at 100$℃$ and during this process temperature again remains constant. Temperature $\mathrm{versus}$ heat supplied graph will be as follows.