A block of mass 1 kg is placed on a truck which accelerates with acceleration 5 m s - 2 . The coefficient of static friction between the block and truck is 0.6 . The frictional force acting on the block is

Question

A block of mass 1 kg is placed on a truck which accelerates with acceleration 5 m s - 2 . The coefficient of static friction between the block and truck is 0.6 . The frictional force acting on the block is, 5 N, 6 N, 5.82 N, 4.6 N

MARKS App · Accepted Answer

Given, a = 5 m s - 2 , m = 1 kg , μ = 0.6 . ∴ Maximum static frictional force f s = μ s mg = 0 . 6 × 1 × 10 = 6 N Force on a block due to acceleration of truck F ext = ma = 1 × 5 = 5 N Hence, F ext f s Therefore, force of friction = external force = 5 N

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