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Question: Answered & Verified by Expert
A block of mass 10 kg is kept on a rough inclined plane as shown in the figure. A force of 3 N is applied on the block. The coefficient of static friction between the plane and the block is 0.6. What should be the minimum value of force P, such that the block does not move downward? (take g=10 ms-2 )

PhysicsLaws of MotionJEE MainJEE Main 2019 (09 Jan Shift 1)
Options:
  • A 23 N
  • B 25 N
  • C 18 N
  • D 32 N
Solution:
2420 Upvotes Verified Answer
The correct answer is: 32 N



Block will be at rest

mgsinθ+3N=P+f

10×10×12+3=P+μmgcosθ

( To get P minimum friction must be minimum)

Pmin=502+3-0.6×10×10×12

=202+3=32N

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