Join the Most Relevant JEE Main 2025 Test Series & get 99+ percentile! Join Now
Search any question & find its solution
Question: Answered & Verified by Expert
A block of mass 10 kg, moving in x direction with a constant speed of 10 s-1 , is subjected to a retarding force F=(0.1)xJ m-1 during its travel from x=20 m to 30 m . Its final kinetic energy will be:
PhysicsWork Power EnergyNEETNEET 2015 (Phase 1)
Options:
  • A 475 J
  • B 450 J
  • C 275 J
  • D 250 J
Solution:
2028 Upvotes Verified Answer
The correct answer is: 475 J
m=10 kg, u=10 m s-1

Final KE will be given by

KEf=KEi+W

=12mu2+2030-0.1xdx

=12×10×100+-0.1x222030 

=500+-0.12900-400

KEf=500+-0.15002=475 J

Looking for more such questions to practice?

Download the MARKS App - The ultimate prep app for IIT JEE & NEET with chapter-wise PYQs, revision notes, formula sheets, custom tests & much more.