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Question: Answered & Verified by Expert
A block of mass 2 kg is kept at origin at t=0 and is having velocity 45 m/s in positive x-direction. The only force on it is a conservative and its potential energy is defined as U=-x3+6x2+15 ( SI units). Its velocity when the force acting on it is minimum (after the time t=0 ) is
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Options:
  • A m/s
  • B m/s
  • C 1024 m/s
  • D none of these
Solution:
1438 Upvotes Verified Answer
The correct answer is: m/s
At x=0

K=12×2×80=80 J and U=15 J

Total energy is,

E=K+U=95 J

Force, F=-dUdx

F=3x2-12x

For F to be minimum, dFdx=0

x=2 m

At x=2 m

E=K+U

95=12×2×v2+-8+24+15

v=8 m/s

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