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A block of mass $2 \mathrm{~kg}$ is placed on the floor. The coefficient of static friction is 0.4 . If a force of $2.8 \mathrm{~N}$ is applied on the block parallel to the floor, the force of friction between the block and the floor is $\left(g=10 \mathrm{~m} \mathrm{~s}^{-2}\right)$
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$2.8 \mathrm{~N}$
$\text { As } f_{m s}=\mu_s m g=0.4 \times 2 \times 10=8 \mathrm{~N} \text {. }$
The applied force of $2.8 \mathrm{~N}$ is less than $f_{m s}(=8 \mathrm{~N})$ and as such the block does not move. When the block is at rest, frictional force $=$ applied force $=2.8 \mathrm{~N}$
The applied force of $2.8 \mathrm{~N}$ is less than $f_{m s}(=8 \mathrm{~N})$ and as such the block does not move. When the block is at rest, frictional force $=$ applied force $=2.8 \mathrm{~N}$
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