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A block of mass $2 \mathrm{~kg}$ is pulled at a constant speed with a taut rope along a frictionless plane that is inclined at $30^{\circ}$. Then the work done by the tension in the rope in pulling it a distance $4 \mathrm{~m}$ along the inclined plane in joule is
$\left(\right.$ acceleration due to gravity $=10 \mathrm{~ms}^{-2}$ )
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$\left(\right.$ acceleration due to gravity $=10 \mathrm{~ms}^{-2}$ )
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Verified Answer
The correct answer is:
$40$
As $V=$ constant
$\begin{aligned} & \Rightarrow \mathrm{T}=\mathrm{mg} \sin \theta \\ & \Rightarrow \mathrm{T}=2 \times 10 \times \sin 30^{\circ} \\ & \Rightarrow \mathrm{T}=10 \mathrm{~N}\end{aligned}$
So, work done $=\mathrm{T} \times \mathrm{x}$
$=10 \times 4=40 \mathrm{~N}$
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