A block of mass 2 kg slides on an inclined plane which makes an angle of 30 ° with the horizontal. The coefficient of friction between the block and the surface is 3 2 . What force along the plane should be applied to the block so that it moves down?

Question

A block of mass 2 kg slides on an inclined plane which makes an angle of 30 ° with the horizontal. The coefficient of friction between the block and the surface is 3 2 . What force along the plane should be applied to the block so that it moves down?, 11 . 21, 4 . 5, 6 . 7, 30 . 14

MARKS App · Accepted Answer

m g sin θ = ( 2 ) ( 10 ) ( 1 2 ) = 10 N = F 1 (say) μ m g cos θ = ( 3 2 ) ( 2 ) ( 10 ) ( 3 2 ) = 21 . 21 N = F 2 (say) Force required to move the block down the plane with constant velocity. F 1 will be acting downwards, while F 2 upwards. Since F 2 > F 1 , force required F = F 2 - F 1 = 11 . 21 N

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