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Question: Answered & Verified by Expert

A block of mass 5 kg is kept against an accelerating wedge with a wedge angle of 45° to the horizontal. The co-efficient of friction between the block and the wedge is μ=0.4. What is the minimum absolute value of the acceleration of the wedge to keep the block steady. Assume g=10 m s-2

PhysicsLaws of MotionTS EAMCETTS EAMCET 2018 (04 May Shift 1)
Options:
  • A 607 m s-2
  • B 307 m s-2
  • C 307 m s-2
  • D 607 m s-2
Solution:
2798 Upvotes Verified Answer
The correct answer is: 307 m s-2

Minimum acceleration, amin=g1-μ1+μ

=101-0.41+0.4=6014

  amin=307m s-2

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