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A block of mass $5 \mathrm{~kg}$ resting on a horizontal surface is connected by a cord, passing over a light frictionless pulley to a hanging block of mass $5 \mathrm{~kg}$. The coefficient of kinetic friction between the block and the surface is $0.5$. Tension in the cord is : $\left(\mathrm{g}=9.8 \mathrm{~m} / \mathrm{sec}^{2}\right)$
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Verified Answer
The correct answer is:
$36.75 \mathrm{~N}$
For block A,
$\mathrm{T}-\mu \mathrm{N}=5 \mathrm{a} \text { and } \mathrm{N}=5 \mathrm{~g}$
For block B,
$$
\begin{array}{l}
5 \mathrm{~g}-\mathrm{T}=5 \mathrm{a} \\
\Rightarrow \mathrm{T}=36.75 \mathrm{~N}, \mathrm{a}=2.45 \mathrm{~m} / \mathrm{sec}^{2}
\end{array}
$$
$\mathrm{T}-\mu \mathrm{N}=5 \mathrm{a} \text { and } \mathrm{N}=5 \mathrm{~g}$
For block B,
$$
\begin{array}{l}
5 \mathrm{~g}-\mathrm{T}=5 \mathrm{a} \\
\Rightarrow \mathrm{T}=36.75 \mathrm{~N}, \mathrm{a}=2.45 \mathrm{~m} / \mathrm{sec}^{2}
\end{array}
$$
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