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Question: Answered & Verified by Expert

A block of mass M1 is constrained to move along with a moveable pulley of mass M2 which is connected to a spring of force constant k, as shown in the figure. If the mass of the fixed pulley is negligible and friction is absent everywhere, then the period of small oscillations of the system is

PhysicsOscillationsJEE Main
Options:
  • A 2π4M1+M2k
  • B 2π4M2+M1k
  • C 4π2M1+M2k
  • D π4M1-M2k
Solution:
1719 Upvotes Verified Answer
The correct answer is: 2π4M1+M2k
If the mass M1 is displaced by x and has speed v, spring will extend by x/2 and M2 will have speed v/2. Energy of this system can be written as

-M1gx+12M1v2+M2gx2+12M2v22+12kx22=const.

-M1gx+12M1v2+M22gx+18M2v2+18kx2=const.

Differentiate wrt time

-M1gv+M1vdvdt+M2g2v+14M2vdvdt+18kx.v=0

-M1g+M1dvdt+M2g2+14M2dvdt+18kx=0



M1+M24dvdt=-k4x+M1g-M2g2

a=dvdt=-k4M1+M2x+22M1-M2g4M1+M2

Here,ω2=k4M1+M2T=2πω=2π4M1+M2k

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