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Question: Answered & Verified by Expert
A block of mass m is kept on an inclined plane of a lift moving down with an acceleration of 2 m s-2. What should be the coefficient of friction for the block to move down with constant velocity relative to lift? The angle of inclination of the wedge is 30°g=10 m s-2

PhysicsLaws of MotionJEE Main
Options:
  • A μ = 1 3
  • B μ = 0 . 4
  • C μ = 0 . 8
  • D μ = 0 . 5
Solution:
1272 Upvotes Verified Answer
The correct answer is: μ = 1 3
geff=g-2=8 m s-2

m 8 sin 30 o =μ.m 8 cos 30 o μ=tan 30 o

⇒         m g - a sin  θ = μ m g - a cos  θ

⇒         μ = tan  θ = tan  3 0 o = 1 3

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