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A block of mass $m$ is moving on a rough horizontal surface. The coefficient of kinetic friction between block and surface is $\mu_{k}$, The net force exerted by the surface on the block is $\quad(\mathrm{g}=$ acceleration due to gravity $)$
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Verified Answer
The correct answer is:
$\mathrm{mg}\left(1+\mu_{\mathrm{k}}^{2}\right)^{1 / 2}$
Given that:
If body of mass \(m\) moving with rough horizontal surface Kinetic fiction = u
\(\begin{aligned} F_{\text {net }} &=\sqrt{f_{1}^{2}+f_{3}{ }^{2}} \\ &=\sqrt{\left(m g^{2}\right)^{2}+(l m g)^{2}} \end{aligned}\)
\(F=m g \sqrt{1+\mu^{2}}=\) option \(A\) is correct
If body of mass \(m\) moving with rough horizontal surface Kinetic fiction = u
\(\begin{aligned} F_{\text {net }} &=\sqrt{f_{1}^{2}+f_{3}{ }^{2}} \\ &=\sqrt{\left(m g^{2}\right)^{2}+(l m g)^{2}} \end{aligned}\)
\(F=m g \sqrt{1+\mu^{2}}=\) option \(A\) is correct
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