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Question: Answered & Verified by Expert
A block of mass m is placed on a smooth inclined wedge ABC of inclination θ as shown in the figure. The wedge is given an acceleration a towards the right. The relation between a and θ for the block to remain stationary on the wedge is

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Options:
  • A a=gcosθ
  • B a=ssinθ
  • C a=gcosceθ
  • D a=gtanθ
Solution:
2731 Upvotes Verified Answer
The correct answer is: a=gtanθ

In non-inertial frame of wedge 

Using pseudo force,
Free body diagram is given as



Normal reaction is balanced by mgcosθ

Where m is mass of the body, 

g is the acceleration due to gravity

a is the acceleration produced by external force..
macosθ=mgsinθ

a=gsinθcosθ

a=gtanθ

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