A block of mass m is placed on a surface having vertical cross section given by y = x 2 4 . If coefficient of friction is 0 . 5 , the maximum height above the ground at which block can be placed without slipping is:

Question

A block of mass m is placed on a surface having vertical cross section given by y = x 2 4 . If coefficient of friction is 0 . 5 , the maximum height above the ground at which block can be placed without slipping is:, 1 4 m, 1 2 m, 1 6 m, 1 3 m

MARKS App · Accepted Answer

At equilibrium, tan θ = μ . Now, tan θ is slope of the curve. Therefore, tan θ = d y d x = x 2 Now, x 2 = 0 . 5 ⇒ x = 1 Required height y = x 2 4 = 1 4 m .

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