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A block of mass $m$ slides from rest at a height $\mathrm{H}$ on a frictionless inclined plane as shown in the figure. It travels a distance d across a rough horizontal surface with coefficient of kinetic friction $\mu$, and compresses a spring of spring $\mathrm{k}$ by a distance $\mathrm{x}$ before coming to rest momentarily. Then the spring extends and the block travels back attaining a final height of $h$. Then
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The correct answer is:
$h=H-2 \mu(d+x)$
$\mathrm{mgH}-2 \mu \mathrm{mg}(\mathrm{d}+\mathrm{x})-\mathrm{mgh}=0$
$\mathrm{~h}=\mathrm{H}-2 \mu(\mathrm{d}+\mathrm{x})$
$\mathrm{~h}=\mathrm{H}-2 \mu(\mathrm{d}+\mathrm{x})$
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