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Question: Answered & Verified by Expert

A block of mass M slides on a frictionless surface with an initial speed of v0. On top of the block, there is a small block of mass m. The coefficient of friction between the blocks is μ. The system of blocks encounters an ideal spring with force constant k. The maximum value of k for which the blocks don't slip relative to each other is

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Options:
  • A μgv02m+M2m
  • B μgv02m+M
  • C μgv02m+M2M
  • D μgv02M-m
Solution:
1801 Upvotes Verified Answer
The correct answer is: μgv02m+M

12M+mv02=12kx2

x=v0M+mk

Also for the upper block

fmax=μmg=mkm+Mx

μg=km+Mv0m+Mk

km+M=μgv02

k=μgv02m+M

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