Join the Most Relevant JEE Main 2025 Test Series & get 99+ percentile! Join Now
Open MARKS Web Download App
Search any question & find its solution
Question: Answered & Verified by Expert


A block of mass $m$ slides with speed $v$ on a frictionless table towards another stationary block of mass $m$. A massless spring with spring constant $\mathrm{k}$ is attached to the second block as shown in figure. The maximum distance the spring gets compress through is
PhysicsWork Power EnergyWBJEEWBJEE 2021
Options:
  • A $\sqrt{\frac{\mathrm{m}}{\mathrm{k}}} \mathrm{v}$
  • B $\sqrt{\frac{m}{2 k}} v$
  • C $\sqrt{\frac{\mathrm{k}}{\mathrm{m}}} \mathrm{v}$
  • D $\sqrt{\frac{\mathrm{k}}{2 \mathrm{~m}}} \mathrm{v}$
Solution:
2672 Upvotes Verified Answer
The correct answer is: $\sqrt{\frac{m}{2 k}} v$
$\frac{1}{2} \mathrm{kx}^{2}=\frac{1}{2} \times \frac{\mathrm{m} \times \mathrm{m}}{2 \mathrm{~m}} \mathrm{v}^{2} \Rightarrow \mathrm{x}=\sqrt{\frac{\mathrm{m}}{2 \mathrm{k}}} \mathrm{v}$

Looking for more such questions to practice?

Download the MARKS App - The ultimate prep app for IIT JEE & NEET with chapter-wise PYQs, revision notes, formula sheets, custom tests & much more.

Use on iOS or Desktop Download from Google Play