A block rests on a rough inclined plane making an angle of 30 ° with the horizontal. The coefficient of static friction between the block and the plane is 0 . 8 . If the frictional force on the block is 10 N , the mass of the block is T a k e g = 10 m s - 2

Question

A block rests on a rough inclined plane making an angle of 30 ° with the horizontal. The coefficient of static friction between the block and the plane is 0 . 8 . If the frictional force on the block is 10 N , the mass of the block is T a k e g = 10 m s - 2, 1 k g, 2 k g, 3 k g, 4 k g

MARKS App · Accepted Answer

As the block is at the state of rest, ∴ R = m g cos ⁡ θ , which is balanced. and f 1 = force of friction = 10 N (given) Hence, f 1 = m g sin ⁡ θ 10 = m × 10 × sin ⁡ 30 o m = 10 10 × sin ⁡ 30 o = 2 k g

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