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A bob is whirled in a horizontal plane by means of a string with an initial speed of $\omega$ rpm. The tension in the string is $T$. If speed becomes $2 \omega$ while keeping the same radius, the tension in the string becomes:
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Verified Answer
The correct answer is:
4T
$T=m \ell \omega^2$
$\begin{aligned} & T^{\prime}=m \ell(2 \omega)^2 \\ & T^{\prime}=4 T\end{aligned}$
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