A bob of pendulum of mass 50 g is suspended by a string with the roof of an elevator. If the lift is falling with a uniform acceleration of 5 m s - 2 , the tension in the string is g = 10 m s - 2

Question

A bob of pendulum of mass 50 g is suspended by a string with the roof of an elevator. If the lift is falling with a uniform acceleration of 5 m s - 2 , the tension in the string is g = 10 m s - 2, 0.5 N, 0.225 N, 0.25 N, 0.025 N

MARKS App · Accepted Answer

Here, mass of bob, m = 50 g = 0.05 kg Since, the lift is falling downward with a uniform acceleration of 5 m s - 2 , hence tension in the string, T = m g - a = 0.05 10 - 5 = 0.05 × 5 = 0.25 N

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