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Question: Answered & Verified by Expert
A body A of mass m=0.1 kg has an initial velocity of 3i^ m s-1. It collides elastically with another body B of the same mass which has an initial velocity of 5j^ m s-1. After the collision, A moves with a velocity v=4i^+j^ m s-1. The energy of B after the collision is written as x10 J. The value of x is
PhysicsCenter of Mass Momentum and CollisionJEE MainJEE Main 2020 (08 Jan Shift 1)
Solution:
1155 Upvotes Verified Answer
The correct answer is: 1

Using the principle of conservation of linear momentum

0.1×3i^ + 0.1×5j^ = 0.1×4i^+j^ + 0.1×v

v=-i^ + j^ m s-1

v=v=2 m s-1

KB=12×0.1×v2=110 J

x=1

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