A body executes S.H.M. of period 20 seconds. Its velocity is 5 cm s - 1 , 2 seconds after it has passed the mean position. Find the amplitude of the bob cos 36 ° = 0 . 809

Question

A body executes S.H.M. of period 20 seconds. Its velocity is 5 cm s - 1 , 2 seconds after it has passed the mean position. Find the amplitude of the bob cos 36 ° = 0 . 809, 21 . 45 cm, 16 . 56 cm, 19 . 67 cm, 15 . 34 cm

MARKS App · Accepted Answer

Here, T = 20 s Also, when t = 2 s , v = 5 cm s - 1 Now, v = A ω cos ωt = A × 2 π T cos 2 π T t ∴ 5 = A × 2 π 2 0 cos 2 π 2 0 × 2 or A π 1 0 cos π 5 = 5 or π A 1 0 cos 36° = 5 or π A 1 0 × 0 . 8 0 9 0 = 5 or A = 19 . 67 cm

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