Search any question & find its solution
Question:
Answered & Verified by Expert
A body initially at rest is acted upon by a constant force (F) for time (t). The kinetic energy at time $\mathrm{t}$ is
Options:
Solution:
1532 Upvotes
Verified Answer
The correct answer is:
$\frac{\mathrm{F}^{2} \mathrm{t}^{2}}{2 \mathrm{~m}}$
acceleration $\mathrm{a}=\frac{\mathrm{F}}{\mathrm{m}}$
At time t, velocity $\mathrm{v}=\mathrm{at}=\frac{\mathrm{Ft}}{\mathrm{m}}$
Kinetic energy $=\frac{1}{2} \mathrm{mv}^{2}$
$=\frac{1}{2} \mathrm{~m} \frac{\mathrm{F}^{2} \mathrm{t}^{2}}{\mathrm{~m}^{2}}=\frac{1}{2} \frac{\mathrm{F}^{2} \mathrm{t}^{2}}{\mathrm{~m}}$
At time t, velocity $\mathrm{v}=\mathrm{at}=\frac{\mathrm{Ft}}{\mathrm{m}}$
Kinetic energy $=\frac{1}{2} \mathrm{mv}^{2}$
$=\frac{1}{2} \mathrm{~m} \frac{\mathrm{F}^{2} \mathrm{t}^{2}}{\mathrm{~m}^{2}}=\frac{1}{2} \frac{\mathrm{F}^{2} \mathrm{t}^{2}}{\mathrm{~m}}$
Looking for more such questions to practice?
Download the MARKS App - The ultimate prep app for IIT JEE & NEET with chapter-wise PYQs, revision notes, formula sheets, custom tests & much more.