A body is projected horizontal on the top of the Mount Everest with speed much greater than $ \sqrt{2 g r} $, where $ r $ is the distance of the projection point from the centre of the earth and $ g $ is the acceleration due to gravity there. The trajectory of the body will be a

Question

A body is projected horizontal on the top of the Mount Everest with speed much greater than $ \sqrt{2 g r} $, where $ r $ is the distance of the projection point from the centre of the earth and $ g $ is the acceleration due to gravity there. The trajectory of the body will be a, straight line, parabola, hyperbola, ellipse

MARKS App · Accepted Answer

Escape velocity if given by v e = 2 g r In astrodynamics or celestial mechanics, a hyperbolic trajectory is the trajectory of any object around a central body with more than enough speed to escape the central object's gravitational pull. The name derives from the fact that according to Newtonian theory such an orbit has the shape of a hyperbola According to question projection speed is much greater than 2 g r . So, body escape from earth along hyperbola.

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