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Question: Answered & Verified by Expert
A body is projected with a velocity $(\hat{\mathrm{i}}+2 \hat{\mathrm{j}}) \mathrm{ms}^{-1}$, where $\hat{\mathrm{i}}$ is along the horizontal and $\hat{\mathrm{j}}$ is vertically upward. Then the equation of its trajectory is $\left(\mathrm{g}=10 \mathrm{~ms}^{-2}\right)$
PhysicsMotion In Two DimensionsAP EAMCETAP EAMCET 2017 (25 Apr Shift 2)
Options:
  • A $y=x-5 x^2$
  • B $y=2 x-5 x^2$
  • C $y=2 x+5 x^2$
  • D $y=x+5 x^2$
Solution:
1489 Upvotes Verified Answer
The correct answer is: $y=2 x-5 x^2$
No solution. Refer to answer key.

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