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Question: Answered & Verified by Expert
A body is projected with an initial velocity of (8i^+6j^) m s-1. The horizontal range is (g=10 m s-2)
PhysicsMotion In Two DimensionsNEET
Options:
  • A 9.6 m
     
  • B 14 m
     
  • C 50 m
  • D 100 m
Solution:
1365 Upvotes Verified Answer
The correct answer is: 9.6 m
 
velocity   = 8 i ^ + 6 j ^

           v = 10 m s - 1

and angle tan θ = 6 8 = 3 4

Range =u2sin2θg=u22sinθcosθg

             = 10 2 2 3 5 4 5 10

             = 48 5 = 9.6 m

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