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A body is whirled in a horizontal circle of radius 25 cm . It has an angular velocity of $13 \mathrm{rad} / \mathrm{s}$. What is its linear velocity at any point on circular path?
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The correct answer is:
$3.25 \mathrm{~m} / \mathrm{s}$
Given, $\begin{aligned} r & =25 \mathrm{~cm}=0.25 \mathrm{~m} \\ \omega & =13 \mathrm{rad} / \mathrm{s}\end{aligned}$
$\because$ Linear speed $=$ Radius $\times$ Angular speed
$\begin{array}{llrl}\text { or } & & v & =r \omega \\ \therefore & & & =0.25 \times 13 \\ \Rightarrow & & v & =3.25 \mathrm{~m} / \mathrm{s}\end{array}$
$\because$ Linear speed $=$ Radius $\times$ Angular speed
$\begin{array}{llrl}\text { or } & & v & =r \omega \\ \therefore & & & =0.25 \times 13 \\ \Rightarrow & & v & =3.25 \mathrm{~m} / \mathrm{s}\end{array}$
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