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Question: Answered & Verified by Expert
A body moves from a position r1=2i^-3j^-4k^ m to a position, r2=(3i^-4j^+5k^) m under the influence of a constant force F=4i^+j^+6k^ N. The work done by the force is
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Options:
  • A 57 J
  • B 58 J
  • C 59 J
  • D 60 J
Solution:
1184 Upvotes Verified Answer
The correct answer is: 57 J
Given,r1=2i^-3j^-4k^

And   r2=3i^-4j^+5k^

Now, r2-r1=i^-j^+9k^

And F=4i^+j^+6k^

         work done = F.r

W=4i^+j^+6k^.(i^-j^+9k^)

     =4-1+54=57 J

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