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A body of density $\rho^{\prime}$ is dropped from rest at a height h into a lake of density $\rho$ where $\rho>\rho^{\prime}$ neglecting all dissipative forces, calculate the maximum depth to which the body sinks before returning to float on the surface:
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The correct answer is:
$\frac{\mathrm{h} \rho^{\prime}}{\rho-\rho^{\prime}}$
The effective acceleration of the body
$\mathrm{g}^{\prime}=\left(1-\frac{\rho}{\rho^{\prime}}\right) \mathrm{g}$

Now, the depth to which the body sinks
$\mathrm{h}^{\prime}=\left(\frac{\mathrm{u}^{2}}{2 \mathrm{~g}^{\prime}}\right)=\frac{2 \mathrm{gh}}{2 \mathrm{~g}^{\prime}}=\frac{\mathrm{gh}}{\mathrm{g}^{\prime}}=\frac{\mathrm{h} \times \rho^{\prime}}{\rho-\rho^{\prime}}$
$\mathrm{g}^{\prime}=\left(1-\frac{\rho}{\rho^{\prime}}\right) \mathrm{g}$

Now, the depth to which the body sinks
$\mathrm{h}^{\prime}=\left(\frac{\mathrm{u}^{2}}{2 \mathrm{~g}^{\prime}}\right)=\frac{2 \mathrm{gh}}{2 \mathrm{~g}^{\prime}}=\frac{\mathrm{gh}}{\mathrm{g}^{\prime}}=\frac{\mathrm{h} \times \rho^{\prime}}{\rho-\rho^{\prime}}$
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