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Question: Answered & Verified by Expert
A body of density $\rho^{\prime}$ is dropped from rest at a height h into a lake of density $\rho$ where $\rho>\rho^{\prime}$ neglecting all dissipative forces, calculate the maximum depth to which the body sinks before returning to float on the surface:
PhysicsMechanical Properties of FluidsBITSATBITSAT 2020
Options:
  • A $\frac{\mathrm{h}}{\rho-\rho^{\prime}}$
  • B $\frac{\mathrm{h} \rho^{\prime}}{\rho}$
  • C $\frac{\mathrm{h} \rho^{\prime}}{\rho-\rho^{\prime}}$
  • D $\frac{h \rho}{\rho-\rho^{\prime}}$
Solution:
1113 Upvotes Verified Answer
The correct answer is: $\frac{\mathrm{h} \rho^{\prime}}{\rho-\rho^{\prime}}$
The effective acceleration of the body

$\mathrm{g}^{\prime}=\left(1-\frac{\rho}{\rho^{\prime}}\right) \mathrm{g}$




Now, the depth to which the body sinks

$\mathrm{h}^{\prime}=\left(\frac{\mathrm{u}^{2}}{2 \mathrm{~g}^{\prime}}\right)=\frac{2 \mathrm{gh}}{2 \mathrm{~g}^{\prime}}=\frac{\mathrm{gh}}{\mathrm{g}^{\prime}}=\frac{\mathrm{h} \times \rho^{\prime}}{\rho-\rho^{\prime}}$

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