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Question: Answered & Verified by Expert
A body of length $1 \mathrm{~m}$ having cross-sectional area $0.75 \mathrm{~m}^{2}$ has heat flow through it at the rate of 6000 Joule/sec. Then find the temperature difference if $\mathrm{K}=200 \mathrm{Jm}^{-1} \mathrm{~K}^{-1}$
PhysicsThermal Properties of MatterBITSATBITSAT 2009
Options:
  • A $20^{\circ} \mathrm{C}$
  • B $40^{\circ} \mathrm{C}$
  • C $80^{\circ} \mathrm{C}$
  • D $100^{\circ} \mathrm{C}$
Solution:
2203 Upvotes Verified Answer
The correct answer is: $40^{\circ} \mathrm{C}$
$\frac{Q}{t}=\frac{\operatorname{KA} \Delta \theta}{\ell} \Rightarrow 6000=\frac{200 \times 0.75 \times \Delta \theta}{1}$
$\therefore \Delta \theta=\frac{6000 \times 1}{200 \times 0.75}=40^{\circ} \mathrm{C}$

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