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A body of length $1 \mathrm{~m}$ having cross-sectional area $0.75 \mathrm{~m}^{2}$ has heat flow through it at the rate of 6000 Joule/sec. Then find the temperature difference if $\mathrm{K}=200 \mathrm{Jm}^{-1} \mathrm{~K}^{-1}$
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The correct answer is:
$40^{\circ} \mathrm{C}$
$\frac{Q}{t}=\frac{\operatorname{KA} \Delta \theta}{\ell} \Rightarrow 6000=\frac{200 \times 0.75 \times \Delta \theta}{1}$
$\therefore \Delta \theta=\frac{6000 \times 1}{200 \times 0.75}=40^{\circ} \mathrm{C}$
$\therefore \Delta \theta=\frac{6000 \times 1}{200 \times 0.75}=40^{\circ} \mathrm{C}$
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