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A body of mass $1 \mathrm{~kg}$ of thrown upwards with a velocity $20 \mathrm{~m} / \mathrm{s}$. It momenetarily comes to rest after attaining a height of $18 \mathrm{~m}$. How much energy is lost due to air friction ?
$$
\left(\mathrm{g}=10 \mathrm{~m} / \mathrm{s}^2\right)
$$
Options:
$$
\left(\mathrm{g}=10 \mathrm{~m} / \mathrm{s}^2\right)
$$
Solution:
2653 Upvotes
Verified Answer
The correct answer is:
$20 \mathrm{~J}$
Loss of energy $=\frac{1}{2} \mathrm{mv}^2-\mathrm{mgh}=20 \mathrm{~J}$
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