A body of mass 1 kg starts moving from rest at t = 0 , in a circular path of radius 8 m . Its kinetic energy varies as a function of times as KE = 2 t 2 Joules, where t is in seconds. Then

Question

A body of mass 1 kg starts moving from rest at t = 0 , in a circular path of radius 8 m . Its kinetic energy varies as a function of times as KE = 2 t 2 Joules, where t is in seconds. Then, Tangential acceleration = 4 m s - 2, Power of all forces at t = 2 s is 8 W, First-round is completed in 2 s ., Tangential force at t = 2 s is 4 N .

MARKS App · Accepted Answer

1 2 m v 2 = 2 t 2 v 2 = 4 t 2 ⇒ v = 2 t a t = d v d t ⇒ a t = 2 m s - 2 F t = m a t ⇒ F t = 2 N Power will be inverted only by tangential force P = F → t + F → c . V → since F c ⊥ V & F t V P = F t V ⇒ P = 2 × 2 t ⇒ P = 4 t ⇒ P = 8 W

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