A body of mass 1 kg tied to a string is just able to move in a vertical circular path of the radius 1 m . The difference between the kinetic energies at its highest and lowest positions of the body is

Question

A body of mass 1 kg tied to a string is just able to move in a vertical circular path of the radius 1 m . The difference between the kinetic energies at its highest and lowest positions of the body is, 4 5 J, 20 J, 10 J, 30 J

MARKS App · Accepted Answer

Kinetic energy is the energy possessed by a body of mass m due to its velocity v . K E = 1 2 m v 2 At the highest point velocity, v A = r g ∴ K E = 1 2 m v A 2 At the lowest point velocity, v B = 5 r g K E = 1 2 m v B 2 Difference n K E = 1 2 m v B 2 - v A 2 = 1 2 m 5 r g - r g = 2 m r g = 2 × 1 × 1 × 10 = 20 J

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