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Question: Answered & Verified by Expert
A body of mass $10 \mathrm{~kg}$ is moving with a constant velocity of $10 \mathrm{~m} / \mathrm{s}$. When a constant force acts for 4 seconds on it, it moves with a velocity $2 \mathrm{~m} / \mathrm{sec}$ in the opposite direction. The acceleration produced in it is
PhysicsMotion In One DimensionJEE Main
Options:
  • A $3 \mathrm{~m} / \mathrm{sec}^2$
  • B $-3 \mathrm{~m} / \mathrm{sec}^2$
  • C $0.3 \mathrm{~m} / \mathrm{sec}^2$
  • D $-0.3 \mathrm{~m} / \mathrm{sec}^2$
Solution:
1145 Upvotes Verified Answer
The correct answer is: $-3 \mathrm{~m} / \mathrm{sec}^2$
$v=u+a t \Rightarrow-2=10+a \times 4 \Rightarrow a=-3 \mathrm{~m} / \mathrm{sec}^2$

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