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A body of mass \(2 \mathrm{~kg}\) moves in a horizontal circular path of radius \(5 \mathrm{~m}\). At an instant, its speed is \(2 \sqrt{5} \mathrm{~m} / \mathrm{s}\) and is increasing at the rate of \(3 \mathrm{~m} / \mathrm{s}^2\). The magnitude of force acting on the body at the instant is,
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Verified Answer
The correct answer is:
\(10 \mathrm{~N}\)
Hint: \(F=\) ma
\(\begin{aligned}
& =m \sqrt{a_c^2+a_T^2} \\
& =m \sqrt{\left(\frac{20}{5}\right)^2+9} \\
& =2 \sqrt{16+9}=2 \times 5=10 \mathrm{~N}
\end{aligned}\)
\(\begin{aligned}
& =m \sqrt{a_c^2+a_T^2} \\
& =m \sqrt{\left(\frac{20}{5}\right)^2+9} \\
& =2 \sqrt{16+9}=2 \times 5=10 \mathrm{~N}
\end{aligned}\)
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