A body of mass 4 kg is accelerated upon by a constant force, travels a distance of 5 m in the first second and a distance of 2 m in the third second. The force acting on the body is

Question

A body of mass 4 kg is accelerated upon by a constant force, travels a distance of 5 m in the first second and a distance of 2 m in the third second. The force acting on the body is, 2 N, 4 N, 6 N, 8 N

MARKS App · Accepted Answer

Distance travelled by the body in n t h second is given by S n = u + a 2 ( 2 n - 1 ) 5 = u + a 2 2 × 1 - 1 5 = u + a 2 … . . i 2 = u + a 2 2 × 3 - 1 2 = u + 5 2 a … . i i Solving Eqs. (i) and (ii), we get a = - 6 4 m s - 2 i e , b o d y is decelerating G i v e n , m a s s = 4 k g ∴ F = m × a = 4 × 6 4 = 6 N

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