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Question: Answered & Verified by Expert
A body of mass M and charge q is connected to a spring of spring constant k. It is oscillating along x-direction about its equilibrium position in the horizontal plane, taken to be at x=0, with an amplitude A. An electric field E is applied along the x-direction. Which of the following statements is correct?
PhysicsOscillationsJEE Main
Options:
  • A The total energy of the system is 12mω2A2+12q2E2k
  • B The new equilibrium position is at a distance 2qEk from x= 0
  • C The new equilibrium position is at a distance qE2k from x= 0
  • D The total energy of the system is 12mω2A2-12q2E2k .
Solution:
1711 Upvotes Verified Answer
The correct answer is: The total energy of the system is 12mω2A2+12q2E2k
The equilibrium position will shift to a point where the resultant force is equal to zero. kxeq=qE  xeq=qEk. Energy =12mω2A2+qEk2=12mω2A2+12q2E2k.

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